model 2 divisibility, multiples, add and subtract based number system Practice Questions Answers Test with Solutions & More Shortcuts

Question : 11

A six digit number is formed by repeating a three digit number; for example, 256, 256 or 678, 678 etc. Any number of this form is always exactly divisible by :

a) 11 only

b) 7 only

c) 1001

d) 13 only

Answer: (c)

The number (x y z x y z) can be written, after giving corresponding weightage of the places at which the digits occur, as 100000 x + 10000y + 1000z + 100x + 10y + z

= 100100x + 10010y + 1001z

= 1001 (100x + 10y + z)

Since 1001 is a factor, the number is divisible by 1001.

7 × 11 × 13 = 1001

As the number is divisible by 1001, it will also be divisible by all three namely, 7, 11 and 13 and not by only one of these because all three are factors of 1001.

So, the answer is 1001.

Question : 12 [SSC Multi-Tasking Staff 2011]

In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, then the dividend is

a) 4306

b) 4236

c) 5336

d) 4336

Answer: (c)

Divisor = 5 × Remainder = 5 × 46 = 230

Quotient = $230/10$ = 23

∴ Dividend = Divisor × Quotient + Remainder

= 230 × 23 + 46

= 5290 + 46 = 5336

Question : 13

The smallest number to be added to 1000, so that 45 divides the sum exactly, is :

a) 80

b) 35

c) 10

d) 20

Answer: (b)

1000 = (45 × 22) + 10

∴ 45 – 10 = 35 to be added.

So, the smallest number to be added to 1000 to make the sum exactly divisible by 45 is 35.

Question : 14

Which of the following number is NOT divisible by 18 ?

a) 50436

b) 54036

c) 65043

d) 34056

Answer: (c)

A number will be exactly divisible by 18 if it is divisible by 2 and 9 both. Clearly 65043 is not divisible by 2.

∴ Required number = 65043

Question : 15

The sum of first sixty numbers from one to sixty is divisible by

a) 59

b) 13

c) 61

d) 60

Answer: (c)

Sum of first 60 numbers

= ${60(60+ 1)}/2$ = ${60× 61}/2$ = 1830

The number 1830 is divisible by 61.

IMPORTANT quantitative aptitude EXERCISES

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